(x+iy)(1+2i)=-1+8i

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Solution for (x+iy)(1+2i)=-1+8i equation: 


Simplifying
(x + iy)(1 + 2i) = -1 + 8i

Reorder the terms:
(iy + x)(1 + 2i) = -1 + 8i

Multiply (iy + x) * (1 + 2i)
(iy(1 + 2i) + x(1 + 2i)) = -1 + 8i
((1 * iy + 2i * iy) + x(1 + 2i)) = -1 + 8i
((1iy + 2i2y) + x(1 + 2i)) = -1 + 8i
(1iy + 2i2y + (1 * x + 2i * x)) = -1 + 8i

Reorder the terms:
(1iy + 2i2y + (2ix + 1x)) = -1 + 8i
(1iy + 2i2y + (2ix + 1x)) = -1 + 8i

Reorder the terms:
(2ix + 1iy + 2i2y + 1x) = -1 + 8i
(2ix + 1iy + 2i2y + 1x) = -1 + 8i

Solving
2ix + 1iy + 2i2y + 1x = -1 + 8i

Solving for variable 'i'.

Reorder the terms:
1 + -8i + 2ix + 1iy + 2i2y + 1x = -1 + 8i + 1 + -8i

Reorder the terms:
1 + -8i + 2ix + 1iy + 2i2y + 1x = -1 + 1 + 8i + -8i

Combine like terms: -1 + 1 = 0
1 + -8i + 2ix + 1iy + 2i2y + 1x = 0 + 8i + -8i
1 + -8i + 2ix + 1iy + 2i2y + 1x = 8i + -8i

Combine like terms: 8i + -8i = 0
1 + -8i + 2ix + 1iy + 2i2y + 1x = 0

The solution to this equation could not be determined.

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