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(x+95)4x=180
We move all terms to the left:
(x+95)4x-(180)=0
We multiply parentheses
4x^2+380x-180=0
a = 4; b = 380; c = -180;
Δ = b2-4ac
Δ = 3802-4·4·(-180)
Δ = 147280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{147280}=\sqrt{16*9205}=\sqrt{16}*\sqrt{9205}=4\sqrt{9205}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(380)-4\sqrt{9205}}{2*4}=\frac{-380-4\sqrt{9205}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(380)+4\sqrt{9205}}{2*4}=\frac{-380+4\sqrt{9205}}{8} $
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