(x+9)(7x-15)=90

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Solution for (x+9)(7x-15)=90 equation:



(x+9)(7x-15)=90
We move all terms to the left:
(x+9)(7x-15)-(90)=0
We multiply parentheses ..
(+7x^2-15x+63x-135)-90=0
We get rid of parentheses
7x^2-15x+63x-135-90=0
We add all the numbers together, and all the variables
7x^2+48x-225=0
a = 7; b = 48; c = -225;
Δ = b2-4ac
Δ = 482-4·7·(-225)
Δ = 8604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{8604}=\sqrt{36*239}=\sqrt{36}*\sqrt{239}=6\sqrt{239}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-6\sqrt{239}}{2*7}=\frac{-48-6\sqrt{239}}{14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+6\sqrt{239}}{2*7}=\frac{-48+6\sqrt{239}}{14} $

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