(x+8)(4x-43)=

Solution for (x+8)(4x-43)= equation:

(x+8)(4x-43)=

We move all terms to the left:

(x+8)(4x-43)-()=0

We add all the numbers together, and all the variables

(x+8)(4x-43)=0

We multiply parentheses ..

(+4x^2-43x+32x-344)=0

We get rid of parentheses

4x^2-43x+32x-344=0

We add all the numbers together, and all the variables

4x^2-11x-344=0

a = 4; b = -11; c = -344;
Δ = b2-4ac
Δ = -112-4·4·(-344)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-75}{2*4}=\frac{-64}{8}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+75}{2*4}=\frac{86}{8}
=10+3/4
$