(x+7)/5+(x-5)/3x/2

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Solution for (x+7)/5+(x-5)/3x/2 equation: 


x in (-oo:+oo)

(x+7)/5+(x*((x-5)/3))/2 = 0

(x+7)/5+(x*(x-5))/(2*3) = 0

(2*3*(x+7))/(2*3*5)+(5*x*(x-5))/(2*3*5) = 0

2*3*(x+7)+5*x*(x-5) = 0

5*x^2-19*x+42 = 0

5*x^2-19*x+42 = 0

5*x^2-19*x+42 = 0

DELTA = (-19)^2-(4*5*42)

DELTA = -479

DELTA < 0

1 = 0

1/(2*3*5) = 0

1/(2*3*5) = 0 // * 2*3*5

1 = 0

x belongs to the empty set

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