(x+7)/4=3-(2x-1)/7

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Solution for (x+7)/4=3-(2x-1)/7 equation: 



(x+7)/4=3-(2x-1)/7

We move all terms to the left:

(x+7)/4-(3-(2x-1)/7)=0

We calculate fractions


x/()+(-(3-(2x-1)*4)/()=0



We calculate terms in parentheses: +(-(3-(2x-1)*4)/(), so:

-(3-(2x-1)*4)/(

We multiply all the terms by the denominator


-(3-(2x-1)*4)



We calculate terms in parentheses: -(3-(2x-1)*4), so:

3-(2x-1)*4

determiningTheFunctionDomain
-(2x-1)*4+3

We multiply parentheses

-8x+4+3

We add all the numbers together, and all the variables

-8x+7

Back to the equation:

-(-8x+7)



We get rid of parentheses

8x-7

Back to the equation:

+(8x-7)



We get rid of parentheses

x/()+8x-7=0

We multiply all the terms by the denominator


x+8x*()-7*()=0

We add all the numbers together, and all the variables

x+8x*()=0

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