(x+7)+(6x+5)=(8x-3)*2

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Solution for (x+7)+(6x+5)=(8x-3)*2 equation:



(x+7)+(6x+5)=(8x-3)*2
We move all terms to the left:
(x+7)+(6x+5)-((8x-3)*2)=0
We get rid of parentheses
x+6x-((8x-3)*2)+7+5=0
We calculate terms in parentheses: -((8x-3)*2), so:
(8x-3)*2
We multiply parentheses
16x-6
Back to the equation:
-(16x-6)
We add all the numbers together, and all the variables
7x-(16x-6)+12=0
We get rid of parentheses
7x-16x+6+12=0
We add all the numbers together, and all the variables
-9x+18=0
We move all terms containing x to the left, all other terms to the right
-9x=-18
x=-18/-9
x=+2

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