(x+6)/3=2+(x-2)/5

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Solution for (x+6)/3=2+(x-2)/5 equation: 



(x+6)/3=2+(x-2)/5

We move all terms to the left:

(x+6)/3-(2+(x-2)/5)=0

We calculate fractions


x/()+(-(2+(x-2)*3)/()=0



We calculate terms in parentheses: +(-(2+(x-2)*3)/(), so:

-(2+(x-2)*3)/(

We multiply all the terms by the denominator


-(2+(x-2)*3)



We calculate terms in parentheses: -(2+(x-2)*3), so:

2+(x-2)*3

determiningTheFunctionDomain
(x-2)*3+2

We multiply parentheses

3x-6+2

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We get rid of parentheses

-3x+4

Back to the equation:

+(-3x+4)



We get rid of parentheses

x/()-3x+4=0

We multiply all the terms by the denominator


x-3x*()+4*()=0

We add all the numbers together, and all the variables

x-3x*()=0

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