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(x+6)(7x)=(x+6)(14)
We move all terms to the left:
(x+6)(7x)-((x+6)(14))=0
We multiply parentheses
7x^2+42x-((x+6)14)=0
We calculate terms in parentheses: -((x+6)14), so:We get rid of parentheses
(x+6)14
We multiply parentheses
14x+84
Back to the equation:
-(14x+84)
7x^2+42x-14x-84=0
We add all the numbers together, and all the variables
7x^2+28x-84=0
a = 7; b = 28; c = -84;
Δ = b2-4ac
Δ = 282-4·7·(-84)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-56}{2*7}=\frac{-84}{14} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+56}{2*7}=\frac{28}{14} =2 $
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