(x+5)/5=4-(x+1)/3

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Solution for (x+5)/5=4-(x+1)/3 equation: 



(x+5)/5=4-(x+1)/3

We move all terms to the left:

(x+5)/5-(4-(x+1)/3)=0

We calculate fractions


x/()+(-(4-(x+1)*5)/()=0



We calculate terms in parentheses: +(-(4-(x+1)*5)/(), so:

-(4-(x+1)*5)/(

We multiply all the terms by the denominator


-(4-(x+1)*5)



We calculate terms in parentheses: -(4-(x+1)*5), so:

4-(x+1)*5

determiningTheFunctionDomain
-(x+1)*5+4

We multiply parentheses

-5x-5+4

We add all the numbers together, and all the variables

-5x-1

Back to the equation:

-(-5x-1)



We get rid of parentheses

5x+1

Back to the equation:

+(5x+1)



We get rid of parentheses

x/()+5x+1=0

We multiply all the terms by the denominator


x+5x*()+1*()=0

We add all the numbers together, and all the variables

x+5x*()=0

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