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(x+5)/(x+1)=32
We move all terms to the left:
(x+5)/(x+1)-(32)=0
Domain of the equation: (x+1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
(x+5)-32*(x+1)=0
We multiply parentheses
(x+5)-32x-32=0
We get rid of parentheses
x-32x+5-32=0
We add all the numbers together, and all the variables
-31x-27=0
We move all terms containing x to the left, all other terms to the right
-31x=27
x=27/-31
x=-27/31
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