(x+5)+8+10=2(x-3)+15+21

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Solution for (x+5)+8+10=2(x-3)+15+21 equation: 



(x+5)+8+10=2(x-3)+15+21

We move all terms to the left:

(x+5)+8+10-(2(x-3)+15+21)=0

We add all the numbers together, and all the variables

(x+5)-(2(x-3)+15+21)+18=0

We get rid of parentheses

x-(2(x-3)+15+21)+5+18=0



We calculate terms in parentheses: -(2(x-3)+15+21), so:

2(x-3)+15+21

We add all the numbers together, and all the variables

2(x-3)+36

We multiply parentheses

2x-6+36

We add all the numbers together, and all the variables

2x+30

Back to the equation:

-(2x+30)



We add all the numbers together, and all the variables

x-(2x+30)+23=0

We get rid of parentheses

x-2x-30+23=0

We add all the numbers together, and all the variables

-1x-7=0

We move all terms containing x to the left, all other terms to the right

-x=7

x=7/-1

x=-7

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