(x+5)+(x+5)+(3x+1)=31

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Solution for (x+5)+(x+5)+(3x+1)=31 equation:


Simplifying
(x + 5) + (x + 5) + (3x + 1) = 31

Reorder the terms:
(5 + x) + (x + 5) + (3x + 1) = 31

Remove parenthesis around (5 + x)
5 + x + (x + 5) + (3x + 1) = 31

Reorder the terms:
5 + x + (5 + x) + (3x + 1) = 31

Remove parenthesis around (5 + x)
5 + x + 5 + x + (3x + 1) = 31

Reorder the terms:
5 + x + 5 + x + (1 + 3x) = 31

Remove parenthesis around (1 + 3x)
5 + x + 5 + x + 1 + 3x = 31

Reorder the terms:
5 + 5 + 1 + x + x + 3x = 31

Combine like terms: 5 + 5 = 10
10 + 1 + x + x + 3x = 31

Combine like terms: 10 + 1 = 11
11 + x + x + 3x = 31

Combine like terms: x + x = 2x
11 + 2x + 3x = 31

Combine like terms: 2x + 3x = 5x
11 + 5x = 31

Solving
11 + 5x = 31

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 5x = 31 + -11

Combine like terms: 11 + -11 = 0
0 + 5x = 31 + -11
5x = 31 + -11

Combine like terms: 31 + -11 = 20
5x = 20

Divide each side by '5'.
x = 4

Simplifying
x = 4

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