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(x+5)(x-49)=52
We move all terms to the left:
(x+5)(x-49)-(52)=0
We multiply parentheses ..
(+x^2-49x+5x-245)-52=0
We get rid of parentheses
x^2-49x+5x-245-52=0
We add all the numbers together, and all the variables
x^2-44x-297=0
a = 1; b = -44; c = -297;
Δ = b2-4ac
Δ = -442-4·1·(-297)
Δ = 3124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3124}=\sqrt{4*781}=\sqrt{4}*\sqrt{781}=2\sqrt{781}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-2\sqrt{781}}{2*1}=\frac{44-2\sqrt{781}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+2\sqrt{781}}{2*1}=\frac{44+2\sqrt{781}}{2} $
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