(x+5)(x+5)=(x-5)(x-5)+10

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Solution for (x+5)(x+5)=(x-5)(x-5)+10 equation: 



(x+5)(x+5)=(x-5)(x-5)+10

We move all terms to the left:

(x+5)(x+5)-((x-5)(x-5)+10)=0

We multiply parentheses ..

(+x^2+5x+5x+25)-((x-5)(x-5)+10)=0



We calculate terms in parentheses: -((x-5)(x-5)+10), so:

(x-5)(x-5)+10

We multiply parentheses ..

(+x^2-5x-5x+25)+10

We get rid of parentheses

x^2-5x-5x+25+10

We add all the numbers together, and all the variables

x^2-10x+35

Back to the equation:

-(x^2-10x+35)



We get rid of parentheses

x^2-x^2+5x+5x+10x+25-35=0

We add all the numbers together, and all the variables

20x-10=0

We move all terms containing x to the left, all other terms to the right

20x=10

x=10/20

x=1/2

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