(x+5)(x+4)(x+3)(x+2)=123456

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Solution for (x+5)(x+4)(x+3)(x+2)=123456 equation: 



(x+5)(x+4)(x+3)(x+2)=123456

We move all terms to the left:

(x+5)(x+4)(x+3)(x+2)-(123456)=0

We multiply parentheses ..

(+x^2+4x+5x+20)(x+3)(x+2)-123456=0

We multiply parentheses ..

(+x^2+4x+5x+20)(+x^2+2x+3x+6)-123456=0

We move all terms containing x to the left, all other terms to the right

(+x^2+4x+5x+20)(+x^2+2x+3x+6)=123456

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