(x+5)(x+2)-3(4x-3)=(5-x)2

Solution for (x+5)(x+2)-3(4x-3)=(5-x)2 equation:

(x+5)(x+2)-3(4x-3)=(5-x)2

We move all terms to the left:

(x+5)(x+2)-3(4x-3)-((5-x)2)=0

We add all the numbers together, and all the variables

(x+5)(x+2)-3(4x-3)-((-1x+5)2)=0

We multiply parentheses

(x+5)(x+2)-12x-((-1x+5)2)+9=0

We multiply parentheses ..

(+x^2+2x+5x+10)-12x-((-1x+5)2)+9=0


We calculate terms in parentheses: -((-1x+5)2), so:

(-1x+5)2

We multiply parentheses

-2x+10

Back to the equation:

-(-2x+10)


We get rid of parentheses

x^2+2x+5x-12x+2x+10-10+9=0

We add all the numbers together, and all the variables

x^2-3x+9=0

a = 1; b = -3; c = +9;
Δ = b2-4ac
Δ = -32-4·1·9
Δ = -27
Delta is less than zero, so there is no solution for the equation