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(x+5)(x+15)=15(x+25)
We move all terms to the left:
(x+5)(x+15)-(15(x+25))=0
We multiply parentheses ..
(+x^2+15x+5x+75)-(15(x+25))=0
We calculate terms in parentheses: -(15(x+25)), so:We get rid of parentheses
15(x+25)
We multiply parentheses
15x+375
Back to the equation:
-(15x+375)
x^2+15x+5x-15x+75-375=0
We add all the numbers together, and all the variables
x^2+5x-300=0
a = 1; b = 5; c = -300;
Δ = b2-4ac
Δ = 52-4·1·(-300)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-35}{2*1}=\frac{-40}{2} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+35}{2*1}=\frac{30}{2} =15 $
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