(x+5)(2x+1)=0

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Solution for (x+5)(2x+1)=0 equation:


Simplifying
(x + 5)(2x + 1) = 0

Reorder the terms:
(5 + x)(2x + 1) = 0

Reorder the terms:
(5 + x)(1 + 2x) = 0

Multiply (5 + x) * (1 + 2x)
(5(1 + 2x) + x(1 + 2x)) = 0
((1 * 5 + 2x * 5) + x(1 + 2x)) = 0
((5 + 10x) + x(1 + 2x)) = 0
(5 + 10x + (1 * x + 2x * x)) = 0
(5 + 10x + (1x + 2x2)) = 0

Combine like terms: 10x + 1x = 11x
(5 + 11x + 2x2) = 0

Solving
5 + 11x + 2x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(5 + x)(1 + 2x) = 0

Subproblem 1

Set the factor '(5 + x)' equal to zero and attempt to solve: Simplifying 5 + x = 0 Solving 5 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + x = 0 + -5 x = 0 + -5 Combine like terms: 0 + -5 = -5 x = -5 Simplifying x = -5

Subproblem 2

Set the factor '(1 + 2x)' equal to zero and attempt to solve: Simplifying 1 + 2x = 0 Solving 1 + 2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2x = 0 + -1 2x = 0 + -1 Combine like terms: 0 + -1 = -1 2x = -1 Divide each side by '2'. x = -0.5 Simplifying x = -0.5

Solution

x = {-5, -0.5}

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