(x+4i)(5+2i)=7+yi

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Solution for (x+4i)(5+2i)=7+yi equation: 


Simplifying
(x + 4i)(5 + 2i) = 7 + yi

Reorder the terms:
(4i + x)(5 + 2i) = 7 + yi

Multiply (4i + x) * (5 + 2i)
(4i * (5 + 2i) + x(5 + 2i)) = 7 + yi
((5 * 4i + 2i * 4i) + x(5 + 2i)) = 7 + yi
((20i + 8i2) + x(5 + 2i)) = 7 + yi
(20i + 8i2 + (5 * x + 2i * x)) = 7 + yi

Reorder the terms:
(20i + 8i2 + (2ix + 5x)) = 7 + yi
(20i + 8i2 + (2ix + 5x)) = 7 + yi

Reorder the terms:
(20i + 2ix + 8i2 + 5x) = 7 + yi
(20i + 2ix + 8i2 + 5x) = 7 + yi

Solving
20i + 2ix + 8i2 + 5x = 7 + iy

Solving for variable 'i'.

Reorder the terms:
-7 + 20i + 2ix + -1iy + 8i2 + 5x = 7 + iy + -7 + -1iy

Reorder the terms:
-7 + 20i + 2ix + -1iy + 8i2 + 5x = 7 + -7 + iy + -1iy

Combine like terms: 7 + -7 = 0
-7 + 20i + 2ix + -1iy + 8i2 + 5x = 0 + iy + -1iy
-7 + 20i + 2ix + -1iy + 8i2 + 5x = iy + -1iy

Combine like terms: iy + -1iy = 0
-7 + 20i + 2ix + -1iy + 8i2 + 5x = 0

The solution to this equation could not be determined.

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