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(x+40)6x+3x(2x+20)=360
We move all terms to the left:
(x+40)6x+3x(2x+20)-(360)=0
We multiply parentheses
6x^2+6x^2+240x+60x-360=0
We add all the numbers together, and all the variables
12x^2+300x-360=0
a = 12; b = 300; c = -360;
Δ = b2-4ac
Δ = 3002-4·12·(-360)
Δ = 107280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{107280}=\sqrt{144*745}=\sqrt{144}*\sqrt{745}=12\sqrt{745}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-12\sqrt{745}}{2*12}=\frac{-300-12\sqrt{745}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+12\sqrt{745}}{2*12}=\frac{-300+12\sqrt{745}}{24} $
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