(x+4/2)=6-(x+4/5)

Solution for (x+4/2)=6-(x+4/5) equation:

(x+4/2)=6-(x+4/5)

We move all terms to the left:

(x+4/2)-(6-(x+4/5))=0

We add all the numbers together, and all the variables

(x+2)-(6-(+x+4/5))=0

We get rid of parentheses

x-(6-(+x+4/5))+2=0

We multiply all the terms by the denominator


x*5))-(6-(+x+4+2*5))=0

We add all the numbers together, and all the variables

x*5))-(6-(x+14))=0

We add all the numbers together, and all the variables

x*5))-(6-(x=0

Wy multiply elements

5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$