(x+4)/3=(2x+1)/2

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Solution for (x+4)/3=(2x+1)/2 equation: 



(x+4)/3=(2x+1)/2

We move all terms to the left:

(x+4)/3-((2x+1)/2)=0

We calculate fractions


x/()+(-((2x+1)*3)/()=0



We calculate terms in parentheses: +(-((2x+1)*3)/(), so:

-((2x+1)*3)/(

We multiply all the terms by the denominator


-((2x+1)*3)



We calculate terms in parentheses: -((2x+1)*3), so:

(2x+1)*3

We multiply parentheses

6x+3

Back to the equation:

-(6x+3)



We get rid of parentheses

-6x-3

Back to the equation:

+(-6x-3)



We get rid of parentheses

x/()-6x-3=0

We multiply all the terms by the denominator


x-6x*()-3*()=0

We add all the numbers together, and all the variables

x-6x*()=0

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