(x+4)/2=7-(x+3)/3

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Solution for (x+4)/2=7-(x+3)/3 equation: 



(x+4)/2=7-(x+3)/3

We move all terms to the left:

(x+4)/2-(7-(x+3)/3)=0

We calculate fractions


x/()+(-(7-(x+3)*2)/()=0



We calculate terms in parentheses: +(-(7-(x+3)*2)/(), so:

-(7-(x+3)*2)/(

We multiply all the terms by the denominator


-(7-(x+3)*2)



We calculate terms in parentheses: -(7-(x+3)*2), so:

7-(x+3)*2

determiningTheFunctionDomain
-(x+3)*2+7

We multiply parentheses

-2x-6+7

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We get rid of parentheses

2x-1

Back to the equation:

+(2x-1)



We get rid of parentheses

x/()+2x-1=0

We multiply all the terms by the denominator


x+2x*()-1*()=0

We add all the numbers together, and all the variables

x+2x*()=0

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