(x+4)/(2)+3x=(2x-3)/(4)

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Solution for (x+4)/(2)+3x=(2x-3)/(4) equation: 



(x+4)/(2)+3x=(2x-3)/(4)

We move all terms to the left:

(x+4)/(2)+3x-((2x-3)/(4))=0

We add all the numbers together, and all the variables

3x+(x+4)/2-((2x-3)/4)=0

We calculate fractions


3x+x/()+(-((2x-3)*2)/()=0



We calculate terms in parentheses: +(-((2x-3)*2)/(), so:

-((2x-3)*2)/(

We multiply all the terms by the denominator


-((2x-3)*2)



We calculate terms in parentheses: -((2x-3)*2), so:

(2x-3)*2

We multiply parentheses

4x-6

Back to the equation:

-(4x-6)



We get rid of parentheses

-4x+6

Back to the equation:

+(-4x+6)



We get rid of parentheses

3x+x/()-4x+6=0

We multiply all the terms by the denominator


3x*()+x-4x*()+6*()=0

We add all the numbers together, and all the variables

x+3x*()-4x*()=0

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