(x+4)+(x+4)+x=50

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Solution for (x+4)+(x+4)+x=50 equation: 



(x+4)+(x+4)+x=50

We move all terms to the left:

(x+4)+(x+4)+x-(50)=0

We add all the numbers together, and all the variables

x+(x+4)+(x+4)-50=0

We get rid of parentheses

x+x+x+4+4-50=0

We add all the numbers together, and all the variables

3x-42=0

We move all terms containing x to the left, all other terms to the right

3x=42

x=42/3

x=14

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