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(x+4)(-2x+4)=0
We multiply parentheses ..
(-2x^2+4x-8x+16)=0
We get rid of parentheses
-2x^2+4x-8x+16=0
We add all the numbers together, and all the variables
-2x^2-4x+16=0
a = -2; b = -4; c = +16;
Δ = b2-4ac
Δ = -42-4·(-2)·16
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-12}{2*-2}=\frac{-8}{-4} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+12}{2*-2}=\frac{16}{-4} =-4 $
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