(x+4)(x-7)=(x+4)(x-3)

Solution for (x+4)(x-7)=(x+4)(x-3) equation:

(x+4)(x-7)=(x+4)(x-3)

We move all terms to the left:

(x+4)(x-7)-((x+4)(x-3))=0

We multiply parentheses ..

(+x^2-7x+4x-28)-((x+4)(x-3))=0


We calculate terms in parentheses: -((x+4)(x-3)), so:

(x+4)(x-3)

We multiply parentheses ..

(+x^2-3x+4x-12)

We get rid of parentheses

x^2-3x+4x-12

We add all the numbers together, and all the variables

x^2+x-12

Back to the equation:

-(x^2+x-12)


We get rid of parentheses

x^2-x^2-7x+4x-x-28+12=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4