(x+4)(x-3)=(x+2)(x-9)

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Solution for (x+4)(x-3)=(x+2)(x-9) equation: 



(x+4)(x-3)=(x+2)(x-9)

We move all terms to the left:

(x+4)(x-3)-((x+2)(x-9))=0

We multiply parentheses ..

(+x^2-3x+4x-12)-((x+2)(x-9))=0



We calculate terms in parentheses: -((x+2)(x-9)), so:

(x+2)(x-9)

We multiply parentheses ..

(+x^2-9x+2x-18)

We get rid of parentheses

x^2-9x+2x-18

We add all the numbers together, and all the variables

x^2-7x-18

Back to the equation:

-(x^2-7x-18)



We get rid of parentheses

x^2-x^2-3x+4x+7x-12+18=0

We add all the numbers together, and all the variables

8x+6=0

We move all terms containing x to the left, all other terms to the right

8x=-6

x=-6/8

x=-3/4

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