(x+4)(x-3)(x-10)=0

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Solution for (x+4)(x-3)(x-10)=0 equation:


Simplifying
(x + 4)(x + -3)(x + -10) = 0

Reorder the terms:
(4 + x)(x + -3)(x + -10) = 0

Reorder the terms:
(4 + x)(-3 + x)(x + -10) = 0

Reorder the terms:
(4 + x)(-3 + x)(-10 + x) = 0

Multiply (4 + x) * (-3 + x)
(4(-3 + x) + x(-3 + x))(-10 + x) = 0
((-3 * 4 + x * 4) + x(-3 + x))(-10 + x) = 0
((-12 + 4x) + x(-3 + x))(-10 + x) = 0
(-12 + 4x + (-3 * x + x * x))(-10 + x) = 0
(-12 + 4x + (-3x + x2))(-10 + x) = 0

Combine like terms: 4x + -3x = 1x
(-12 + 1x + x2)(-10 + x) = 0

Multiply (-12 + 1x + x2) * (-10 + x)
(-12(-10 + x) + 1x * (-10 + x) + x2(-10 + x)) = 0
((-10 * -12 + x * -12) + 1x * (-10 + x) + x2(-10 + x)) = 0
((120 + -12x) + 1x * (-10 + x) + x2(-10 + x)) = 0
(120 + -12x + (-10 * 1x + x * 1x) + x2(-10 + x)) = 0
(120 + -12x + (-10x + 1x2) + x2(-10 + x)) = 0
(120 + -12x + -10x + 1x2 + (-10 * x2 + x * x2)) = 0
(120 + -12x + -10x + 1x2 + (-10x2 + x3)) = 0

Combine like terms: -12x + -10x = -22x
(120 + -22x + 1x2 + -10x2 + x3) = 0

Combine like terms: 1x2 + -10x2 = -9x2
(120 + -22x + -9x2 + x3) = 0

Solving
120 + -22x + -9x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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