(x+4)(x+2)=0

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Solution for (x+4)(x+2)=0 equation:


Simplifying
(x + 4)(x + 2) = 0

Reorder the terms:
(4 + x)(x + 2) = 0

Reorder the terms:
(4 + x)(2 + x) = 0

Multiply (4 + x) * (2 + x)
(4(2 + x) + x(2 + x)) = 0
((2 * 4 + x * 4) + x(2 + x)) = 0
((8 + 4x) + x(2 + x)) = 0
(8 + 4x + (2 * x + x * x)) = 0
(8 + 4x + (2x + x2)) = 0

Combine like terms: 4x + 2x = 6x
(8 + 6x + x2) = 0

Solving
8 + 6x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(4 + x)(2 + x) = 0

Subproblem 1

Set the factor '(4 + x)' equal to zero and attempt to solve: Simplifying 4 + x = 0 Solving 4 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + x = 0 + -4 x = 0 + -4 Combine like terms: 0 + -4 = -4 x = -4 Simplifying x = -4

Subproblem 2

Set the factor '(2 + x)' equal to zero and attempt to solve: Simplifying 2 + x = 0 Solving 2 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Solution

x = {-4, -2}

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