(x+4)(x+)=(x+2)(x+1)

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Solution for (x+4)(x+)=(x+2)(x+1) equation: 



(x+4)(x+)=(x+2)(x+1)

We move all terms to the left:

(x+4)(x+)-((x+2)(x+1))=0

We add all the numbers together, and all the variables

(x+4)(+x)-((x+2)(x+1))=0

We multiply parentheses ..

(+x^2+4x)-((x+2)(x+1))=0



We calculate terms in parentheses: -((x+2)(x+1)), so:

(x+2)(x+1)

We multiply parentheses ..

(+x^2+x+2x+2)

We get rid of parentheses

x^2+x+2x+2

We add all the numbers together, and all the variables

x^2+3x+2

Back to the equation:

-(x^2+3x+2)



We get rid of parentheses

x^2-x^2+4x-3x-2=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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