(x+32)=(3x+20)

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Solution for (x+32)=(3x+20) equation: 



(x+32)=(3x+20)

We move all terms to the left:

(x+32)-((3x+20))=0

We get rid of parentheses

x-((3x+20))+32=0



We calculate terms in parentheses: -((3x+20)), so:

(3x+20)

We get rid of parentheses

3x+20

Back to the equation:

-(3x+20)



We get rid of parentheses

x-3x-20+32=0

We add all the numbers together, and all the variables

-2x+12=0

We move all terms containing x to the left, all other terms to the right

-2x=-12

x=-12/-2

x=+6

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