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(x+30)x=8800
We move all terms to the left:
(x+30)x-(8800)=0
We multiply parentheses
x^2+30x-8800=0
a = 1; b = 30; c = -8800;
Δ = b2-4ac
Δ = 302-4·1·(-8800)
Δ = 36100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36100}=190$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-190}{2*1}=\frac{-220}{2} =-110 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+190}{2*1}=\frac{160}{2} =80 $
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