(x+30)+(4x)+(3x-10)=180

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Solution for (x+30)+(4x)+(3x-10)=180 equation: 



(x+30)+(4x)+(3x-10)=180

We move all terms to the left:

(x+30)+(4x)+(3x-10)-(180)=0

We add all the numbers together, and all the variables

4x+(x+30)+(3x-10)-180=0

We get rid of parentheses

4x+x+3x+30-10-180=0

We add all the numbers together, and all the variables

8x-160=0

We move all terms containing x to the left, all other terms to the right

8x=160

x=160/8

x=20

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