(x+3/x)+(7x/x+3)=23/4

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Solution for (x+3/x)+(7x/x+3)=23/4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+3/x+(7*x)/x+3 = 23/4 // - 23/4

x+3/x+(7*x)/x-(23/4)+3 = 0

x+3/x+(7*x)/x-23/4+3 = 0

1*x^1+3*x^-1+17/4*x^0 = 0

(1*x^2+17/4*x^1+3*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+17/4*x^1+3*x^0) = 0

x^1

x^2+(17/4)*x+3 = 0

x^2+(17/4)*x+3 = 0

DELTA = (17/4)^2-(1*3*4)

DELTA = 97/16

DELTA > 0

x = ((97/16)^(1/2)-(17/4))/(1*2) or x = (-(17/4)-(97/16)^(1/2))/(1*2)

x = ((97/16)^(1/2)-17/4)/2 or x = (-((97/16)^(1/2)+17/4))/2

x in { (-((97/16)^(1/2)+17/4))/2, ((97/16)^(1/2)-17/4)/2} 

x in { (-((97/16)^(1/2)+17/4))/2, ((97/16)^(1/2)-17/4)/2 }

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