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(x+3)x=154
We move all terms to the left:
(x+3)x-(154)=0
We multiply parentheses
x^2+3x-154=0
a = 1; b = 3; c = -154;
Δ = b2-4ac
Δ = 32-4·1·(-154)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-25}{2*1}=\frac{-28}{2} =-14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+25}{2*1}=\frac{22}{2} =11 $
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