(x+3)2=x2+5x

Solution for (x+3)2=x2+5x equation:

(x+3)2=x2+5x

We move all terms to the left:

(x+3)2-(x2+5x)=0

We add all the numbers together, and all the variables

-(+x^2+5x)+(x+3)2=0

We multiply parentheses

-(+x^2+5x)+2x+6=0

We get rid of parentheses

-x^2-5x+2x+6=0

We add all the numbers together, and all the variables

-1x^2-3x+6=0

a = -1; b = -3; c = +6;
Δ = b2-4ac
Δ = -32-4·(-1)·6
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{33}}{2*-1}=\frac{3-\sqrt{33}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{33}}{2*-1}=\frac{3+\sqrt{33}}{-2}
$