(x+3)/5=(4x-3)/15

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Solution for (x+3)/5=(4x-3)/15 equation: 



(x+3)/5=(4x-3)/15

We move all terms to the left:

(x+3)/5-((4x-3)/15)=0

We calculate fractions


x/()+(-((4x-3)*5)/()=0



We calculate terms in parentheses: +(-((4x-3)*5)/(), so:

-((4x-3)*5)/(

We multiply all the terms by the denominator


-((4x-3)*5)



We calculate terms in parentheses: -((4x-3)*5), so:

(4x-3)*5

We multiply parentheses

20x-15

Back to the equation:

-(20x-15)



We get rid of parentheses

-20x+15

Back to the equation:

+(-20x+15)



We get rid of parentheses

x/()-20x+15=0

We multiply all the terms by the denominator


x-20x*()+15*()=0

We add all the numbers together, and all the variables

x-20x*()=0

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