(x+3)/4=x/2+7/20

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Solution for (x+3)/4=x/2+7/20 equation:


x in (-oo:+oo)

(x+3)/4 = x/2+7/20 // - x/2+7/20

(x+3)/4-(x/2)-(7/20) = 0

(x+3)/4-(x/2)-7/20 = 0

(x+3)/4-x/2-7/20 = 0

(2*20*(x+3))/(2*4*20)+(4*20*(-x))/(2*4*20)+(-7*2*4)/(2*4*20) = 0

2*20*(x+3)+4*20*(-x)-7*2*4 = 0

120-40*x-56 = 0

64-40*x = 0

(64-40*x)/(2*4*20) = 0

(64-40*x)/(2*4*20) = 0 // * 2*4*20

64-40*x = 0

64-40*x = 0 // - 64

-40*x = -64 // : -40

x = -64/(-40)

x = 8/5

x = 8/5

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