(x+3)/4=(x/2)+(1/6)

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Solution for (x+3)/4=(x/2)+(1/6) equation: 


x in (-oo:+oo)

(x+3)/4 = x/2+1/6 // - x/2+1/6

(x+3)/4-(x/2)-(1/6) = 0

(x+3)/4-(x/2)-1/6 = 0

(x+3)/4-x/2-1/6 = 0

(2*6*(x+3))/(2*4*6)+(4*6*(-x))/(2*4*6)+(-1*2*4)/(2*4*6) = 0

2*6*(x+3)+4*6*(-x)-1*2*4 = 0

36-12*x-8 = 0

28-12*x = 0

(28-12*x)/(2*4*6) = 0

(28-12*x)/(2*4*6) = 0 // * 2*4*6

28-12*x = 0

28-12*x = 0 // - 28

-12*x = -28 // : -12

x = -28/(-12)

x = 7/3

x = 7/3

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