(x+3)/3=5-(x+2)/7

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Solution for (x+3)/3=5-(x+2)/7 equation: 



(x+3)/3=5-(x+2)/7

We move all terms to the left:

(x+3)/3-(5-(x+2)/7)=0

We calculate fractions


x/()+(-(5-(x+2)*3)/()=0



We calculate terms in parentheses: +(-(5-(x+2)*3)/(), so:

-(5-(x+2)*3)/(

We multiply all the terms by the denominator


-(5-(x+2)*3)



We calculate terms in parentheses: -(5-(x+2)*3), so:

5-(x+2)*3

determiningTheFunctionDomain
-(x+2)*3+5

We multiply parentheses

-3x-6+5

We add all the numbers together, and all the variables

-3x-1

Back to the equation:

-(-3x-1)



We get rid of parentheses

3x+1

Back to the equation:

+(3x+1)



We get rid of parentheses

x/()+3x+1=0

We multiply all the terms by the denominator


x+3x*()+1*()=0

We add all the numbers together, and all the variables

x+3x*()=0

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