(x+3)/2=(2x-1)/5

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Solution for (x+3)/2=(2x-1)/5 equation: 



(x+3)/2=(2x-1)/5

We move all terms to the left:

(x+3)/2-((2x-1)/5)=0

We calculate fractions


x/()+(-((2x-1)*2)/()=0



We calculate terms in parentheses: +(-((2x-1)*2)/(), so:

-((2x-1)*2)/(

We multiply all the terms by the denominator


-((2x-1)*2)



We calculate terms in parentheses: -((2x-1)*2), so:

(2x-1)*2

We multiply parentheses

4x-2

Back to the equation:

-(4x-2)



We get rid of parentheses

-4x+2

Back to the equation:

+(-4x+2)



We get rid of parentheses

x/()-4x+2=0

We multiply all the terms by the denominator


x-4x*()+2*()=0

We add all the numbers together, and all the variables

x-4x*()=0

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