(x+3)+y=(x+3)+4y

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Solution for (x+3)+y=(x+3)+4y equation:


Simplifying
(x + 3) + y = (x + 3) + 4y

Reorder the terms:
(3 + x) + y = (x + 3) + 4y

Remove parenthesis around (3 + x)
3 + x + y = (x + 3) + 4y

Reorder the terms:
3 + x + y = (3 + x) + 4y

Remove parenthesis around (3 + x)
3 + x + y = 3 + x + 4y

Add '-3' to each side of the equation.
3 + x + -3 + y = 3 + x + -3 + 4y

Reorder the terms:
3 + -3 + x + y = 3 + x + -3 + 4y

Combine like terms: 3 + -3 = 0
0 + x + y = 3 + x + -3 + 4y
x + y = 3 + x + -3 + 4y

Reorder the terms:
x + y = 3 + -3 + x + 4y

Combine like terms: 3 + -3 = 0
x + y = 0 + x + 4y
x + y = x + 4y

Add '-1x' to each side of the equation.
x + -1x + y = x + -1x + 4y

Combine like terms: x + -1x = 0
0 + y = x + -1x + 4y
y = x + -1x + 4y

Combine like terms: x + -1x = 0
y = 0 + 4y
y = 4y

Solving
y = 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
y + -4y = 4y + -4y

Combine like terms: y + -4y = -3y
-3y = 4y + -4y

Combine like terms: 4y + -4y = 0
-3y = 0

Divide each side by '-3'.
y = 0

Simplifying
y = 0

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