(x+3)*(x+35)=320

Solution for (x+3)*(x+35)=320 equation:

(x+3)(x+35)=320

We move all terms to the left:

(x+3)(x+35)-(320)=0

We multiply parentheses ..

(+x^2+35x+3x+105)-320=0

We get rid of parentheses

x^2+35x+3x+105-320=0

We add all the numbers together, and all the variables

x^2+38x-215=0

a = 1; b = 38; c = -215;
Δ = b2-4ac
Δ = 382-4·1·(-215)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-48}{2*1}=\frac{-86}{2}
=-43
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+48}{2*1}=\frac{10}{2}
=5
$