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(x+3)(x-3)-x(x+5)=6
We move all terms to the left:
(x+3)(x-3)-x(x+5)-(6)=0
We use the square of the difference formula
x^2-x(x+5)-9-6=0
We multiply parentheses
x^2-x^2-5x-9-6=0
We add all the numbers together, and all the variables
-5x-15=0
We move all terms containing x to the left, all other terms to the right
-5x=15
x=15/-5
x=-3
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