(x+3)(x-1)+5=0

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Solution for (x+3)(x-1)+5=0 equation:


Simplifying
(x + 3)(x + -1) + 5 = 0

Reorder the terms:
(3 + x)(x + -1) + 5 = 0

Reorder the terms:
(3 + x)(-1 + x) + 5 = 0

Multiply (3 + x) * (-1 + x)
(3(-1 + x) + x(-1 + x)) + 5 = 0
((-1 * 3 + x * 3) + x(-1 + x)) + 5 = 0
((-3 + 3x) + x(-1 + x)) + 5 = 0
(-3 + 3x + (-1 * x + x * x)) + 5 = 0
(-3 + 3x + (-1x + x2)) + 5 = 0

Combine like terms: 3x + -1x = 2x
(-3 + 2x + x2) + 5 = 0

Reorder the terms:
-3 + 5 + 2x + x2 = 0

Combine like terms: -3 + 5 = 2
2 + 2x + x2 = 0

Solving
2 + 2x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + 2x + -2 + x2 = 0 + -2

Reorder the terms:
2 + -2 + 2x + x2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 2x + x2 = 0 + -2
2x + x2 = 0 + -2

Combine like terms: 0 + -2 = -2
2x + x2 = -2

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -2 + 1

Reorder the terms:
1 + 2x + x2 = -2 + 1

Combine like terms: -2 + 1 = -1
1 + 2x + x2 = -1

Factor a perfect square on the left side:
(x + 1)(x + 1) = -1

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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