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(x+3)(x+6)/2=119
We move all terms to the left:
(x+3)(x+6)/2-(119)=0
We multiply parentheses ..
(+x^2+6x+3x+18)/2-119=0
We multiply all the terms by the denominator
(+x^2+6x+3x+18)-119*2=0
We add all the numbers together, and all the variables
(+x^2+6x+3x+18)-238=0
We get rid of parentheses
x^2+6x+3x+18-238=0
We add all the numbers together, and all the variables
x^2+9x-220=0
a = 1; b = 9; c = -220;
Δ = b2-4ac
Δ = 92-4·1·(-220)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-31}{2*1}=\frac{-40}{2} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+31}{2*1}=\frac{22}{2} =11 $
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