(x+3)(x+4)=-12

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Solution for (x+3)(x+4)=-12 equation: 



(x+3)(x+4)=-12

We move all terms to the left:

(x+3)(x+4)-(-12)=0

We add all the numbers together, and all the variables

(x+3)(x+4)+12=0

We multiply parentheses ..

(+x^2+4x+3x+12)+12=0

We get rid of parentheses

x^2+4x+3x+12+12=0

We add all the numbers together, and all the variables

x^2+7x+24=0

a = 1; b = 7; c = +24;
Δ = b2-4ac
Δ = 72-4·1·24
Δ = -47
Delta is less than zero, so there is no solution for the equation

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