(x+3)(x+3)=(x-3)16

Solution for (x+3)(x+3)=(x-3)16 equation:

(x+3)(x+3)=(x-3)16

We move all terms to the left:

(x+3)(x+3)-((x-3)16)=0

We multiply parentheses ..

(+x^2+3x+3x+9)-((x-3)16)=0


We calculate terms in parentheses: -((x-3)16), so:

(x-3)16

We multiply parentheses

16x-48

Back to the equation:

-(16x-48)


We get rid of parentheses

x^2+3x+3x-16x+9+48=0

We add all the numbers together, and all the variables

x^2-10x+57=0

a = 1; b = -10; c = +57;
Δ = b2-4ac
Δ = -102-4·1·57
Δ = -128
Delta is less than zero, so there is no solution for the equation